## Find the limit by solving equation II

Solution to Elementary Analysis: The Theory of Calculus Second Edition Section 9 Exercise 9.5 The idea is pretty much the same as Exercise 9.4. Solution: Since $(t_n)$ converges. Set $\lim…

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Solution to Elementary Analysis: The Theory of Calculus Second Edition Section 9 Exercise 9.5 The idea is pretty much the same as Exercise 9.4. Solution: Since $(t_n)$ converges. Set $\lim…

Solution to Elementary Analysis: The Theory of Calculus Second Edition Section 9 Exercise 9.4 Solution: Part a $s_1=1$, $s_2=\sqrt{2}$, $s_3=\sqrt{\sqrt 2+1}$, $s_4=\sqrt{\sqrt{\sqrt 2+1}+1}$. Part b Since $(s_n)$ converges. Set $\lim…

Solution to Elementary Analysis: The Theory of Calculus Second Edition Section 9 Exercise 9.3 Solution: By Theorem 9.4, we have$$\lim a_n^3=(\lim a_n)^3=a^3,\quad \lim b_n^2=(\lim b_n)^2=b^2$$ By Theorem 9.2, we have$$\lim…

Solution to Elementary Analysis: The Theory of Calculus Second Edition Section 9 Exercise 9.2 Solution: Part aBy Theorem 9.3, we have$$\lim(x_n+y_n)=\lim x_n+\lim y_n=3+7=10.$$ Part bBy Theorems 9.2 and 9.3 we…

Solution to Elementary Analysis: The Theory of Calculus Second Edition Section 9 Exercise 9.1 Solution: Part aLet $s_n=\dfrac{n+1}{n}$. We have$$s_n=1+\frac{1}{n}.$$ By Theorem 9.7(a) we have $\lim\dfrac{1}{n}=0$. Thus by Theorem 9.3,…

Solution to Elementary Analysis: The Theory of Calculus Second Edition Section 8 Exercise 8.10 This part actually has been shown in Exercise 8.9. Solution: Suppose $\lim s_n=s$. Then we have…

Solution to Elementary Analysis: The Theory of Calculus Second Edition Section 8 Exercise 8.9 Solution: Part aWe argue it by contradiction. Suppose $\lim s_n=s < a$. Then $a-s >0$. Since…

Solution to Elementary Analysis: The Theory of Calculus Second Edition Section 8 Exercise 8.8 We shall use the following useful formula. $\sqrt{a}-b=\dfrac{a-b^2}{\sqrt{a}+b}$, which is a variation of $(a-b)(a+b)=a^2-b^2$. Solution: Part…

Solution to Elementary Analysis: The Theory of Calculus Second Edition Section 8 Exercise 8.7 Solution: Part aSuppose the limit exists and equals $a$. Then for $\epsilon=\dfrac{1}{2}$, there exists $N>0$ such…

Solution to Elementary Analysis: The Theory of Calculus Second Edition Section 8 Exercise 8.6 Solution: Part aWe first show that if $\lim s_n=0$ then $\lim |s_n|=0$. Let $\epsilon>0$. Since $\lim…