Solution to Elementary Analysis: The Theory of Calculus Second Edition Section 8 Exercise 8.5 Solution: Part a Let $\epsilon>0$. Since $\lim a_n=s$, there exists $N_1>0$ such that $$ |a_n-s|<\epsilon\Longrightarrow -\epsilon…
Solution to Elementary Analysis: The Theory of Calculus Second Edition Section 8 Exercise 8.4 Solution: Let $\epsilon>0$. Since $\lim s_n=0$, there exists $N>0$ such that $$ |s_n-0|=s_n < \frac{\epsilon}{M+1} $$…
Solution to Elementary Analysis: The Theory of Calculus Second Edition Section 8 Exercise 8.3 Solution: Let $\epsilon>0$. Since $\lim s_n=0$, there exists $N>0$ such that $$ |s_n-0|=s_n < \epsilon^2 $$…
Solution to Elementary Analysis: The Theory of Calculus Second Edition Section 8 Exercise 8.2 Solution: Part aThe limit is zero. Let $\epsilon>0$ and let $N=\dfrac{1}{\epsilon}$. Then $n>N$ implies$$\frac{n}{n^2+1}<\frac{n}{n^2}=\frac{1}{n}<\frac{1}{N}=\epsilon,$$ and hence$$\left|\frac{n}{n^2+1}-0\right|=\frac{n}{n^2+1}<\epsilon$$…
Solution to Elementary Analysis: The Theory of Calculus Second Edition Section 8 Exercise 8.1 Solution: Part a Let $\epsilon>0$ and let $N=\dfrac{1}{\epsilon}$. Then $n>N$ implies $$ \frac{1}{n}<\frac{1}{N}=\epsilon, $$ and hence…
Solution to Elementary Analysis: The Theory of Calculus Second Edition Section 7 Exercise 7.5 We shall use the following useful formula. $\sqrt{a}-b=\dfrac{a-b^2}{\sqrt{a}+b}$, which is a variation of $(a-b)(a+b)=a^2-b^2$. Solution: Part…
Solution to Elementary Analysis: The Theory of Calculus Second Edition Section 7 Exercise 7.4 Solution: Part aLet $x_n=\dfrac{1}{\sqrt{n^2+1}}$, then it is clear that all $x_n$ are irrational. However, the sequence…
Solution to Elementary Analysis: The Theory of Calculus Second Edition Section 7 Exercise 7.3 Solution: (a) Converges. Limits is 1. (b) Converges. Limits is 1. (c) Converges. Limits is 0.…
Solution to Elementary Analysis: The Theory of Calculus Second Edition Section 7 Exercise 7.2 Solution: (a) Converges. Limits is 0. (b) Converges. Limits is $3/4$. See Example 2,$$\frac{3n+1}{4n-1}=\frac{3+\frac{1}{n}}{4-\frac{1}{n}}.$$ (c) Converges.…
Solution to Elementary Analysis: The Theory of Calculus Second Edition Section 7 Exercises 7.1 Solution: (a) $s_1=1/4$, $s_2=1/7$, $s_3=1/10$, $s_4=1/13$, $s_5=1/16$. (b) $b_1=4/3$, $b_2=1$, $b_3=10/11$, $b_4=13/15$, $b_5=16/19$. (c) $c_1=1/3$, $c_2=2/9$,…