If you find any mistakes, please make a comment! Thank you.

Elements of generalized coordinate subgroups commute pairwise

Solution to Abstract Algebra by Dummit & Foote 3rd edition Chapter 5.1 Exercise 5.1.3

Solution: Let $x = (x_j)$ and $y = (y_j)$.

If $j \in I$, then $$(xy)_j = x_j y_j = x_j \cdot 1 = 1 \cdot x_j = y_jx_j = (yx)_j.$$ If $j \in K$, then $$(xy)_j = x_j y_j = 1 \cdot y_j = y_j \cdot 1 = y_jx_j = (yx)_j.$$ Otherwise, $$(xy)_j = x_j y_j = 1 \cdot 1 = y_j \cdot x_j = (yx)_j.$$ Thus $xy = yx$.


This website is supposed to help you study Linear Algebras. Please only read these solutions after thinking about the problems carefully. Do not just copy these solutions.
Close Menu