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## Verify if they are sesqui-linear forms

Solution to Linear Algebra Hoffman & Kunze Chapter 9.2 Exercise 9.2.1

Solution:

(a) No. Since $f(0,\beta)\ne 0$.

(b) No. Since $f((0,0),(1,0))\ne 0$.

(c) Yes. Since $f(\alpha,\beta)=4x_1\bar y_1$.

(d) No. Because of $\bar x_2$ there, it is not linear on $\alpha$.